Inductor and Capacitor MCQs : Here you will find MCQ Questions related to "Inductor and Capacitor" in Electric Circuits. These Inductor and Capacitor Sources MCQ Questions Will help you to improve your Electric Circuits knowledge and will prepare you for various Examinations like Competitive Exams, Placements, Interviews and other Entrance Exmaniations.
The formula used to find the capacitance C is ?
Explanation: Q=cv. Q-charge, V-voltage, c-capacitance.
The capacitor doesn’t allow sudden changes in?
Explanation: Any small change in voltage occurs within zero time across the gives an infinite current which is practically impossible. So, in a fixed capacitor, the voltage cannot change abruptly.
The Inductor doesn’t allow sudden changes in?
Explanation: Any small change in current occurs within zero time across the gives an infinite voltage which is practically impossible. So, in a fixed inductor, the voltage cannot change abruptly.
The expression for energy of an inductor?
A. (1/2) LI
C. ½ (L^2)I
D. ½ L(I^2)
Explanation: E=∫p dt =∫ LI*(dI/dt).dt = L∫I dI = ½ LI2.
The units for inductance is _________ and capacitance is ___________
A. Faraday, Henry
B. Coulomb, Faraday
C. Henry, Faraday
D. Henry, Coulomb
Explanation: The unit for inductance is ‘Henry’ and capacitance is ‘Faraday’.
If a capacitor of capacitance 9.2F has a voltage of 22.5V across it. Calculate the energy of the capacitor.
Explanation: E= ½ cv^2.
The voltage applied to a pure capacitor of 50*10-6 F is as shown in figure. Calculate the current for 0-1msec
Explanation: For 0≤t≤1msec,
V (t) =m*t (y=mx form)
→100= 1*10^(-3)*m →m= 1*(10^5)
→ V (t) = 1*(10^5)t
Current I (t) = c. d (v (t))/dt = 50*(10^-6)* (d (1*(10^5)t)/dt) = 5A.
The conducting surfaces are called electrodes and the insulating medium is called?
B. Capacitive medium
C. Conducting medium
Explanation: The conducting surfaces are called electrodes and the insulating medium is called Dielectric
Induced voltage across an inductor is?
Explanation: Induced voltage across an inductor is zero if the current flowing through it is constant. I.e. Inductor works as a short circuit for DC supply.
If the voltage across a capacitor is constant, then current passing through it is ?
Explanation: I= c*(dv/dt).