Source Transformations MCQs : Here you will find MCQ Questions related to "Source Transformations" in Electric Circuits. These Voltage and Current Sources MCQ Questions Will help you to improve your Electric Circuits knowledge and will prepare you for various Examinations like Competitive Exams, Placements, Interviews and other Entrance Exmaniations.
In Source transformation, a voltage source in ________ with a resistor is replaced by a current source in _________ with the same resistor
A. series, parallel
B. series, series
C. parallel, parallel
D. None of the above
Explanation: In Source transformation, a voltage source in series with a resistor is replaced by a current source in parallel with the same resistor and vice versa.
Source Transformation is _____________
Explanation: In Source transformation, a voltage source in series with a resistor is replaced by a current source in parallel with the same resistor and vice versa. So, it is bilateral.
Using source transformation, calculate the voltage.
Which element(s) has no effect in the given circuit?
A. 6 ohms
B. 7 ohms
C. 10 ohms
D. 9 ohms
Explanation: Voltage in series with a resistor in replaced by a current source but here 10Ω is in parallel. So, it is redundant and has no effect.
If there is a 12A current source in series with 2Ω and in parallel with a 4Ω resistor, then voltage V=?
A. 16 watt
B. 32 watt
C. 40 watt
D. 48 watt
Explanation: 2Ω resistor is redundant. 12*4=48V.
Source transformation can be used for dependent sources
C. Can be true or false
D. Can not say
Explanation: Source transformation can be used for dependent sources. However, the controlling variable must not be tampered with any way since the controlled source operation depends on it.
Ohm’s law: V=iR. By using this, the voltage/ current sources are?
D. None of the above
Explanation: Ohm’s law: V=iR. By using this, the voltage/ current sources are reduced.
Find the current flowing through 4Ω resistor shown in network below.
Explanation: By using source transformation the above network is reduced and then by current division rule I4Ω= 5*(2/2+4) =1.66A.
Calculate the power delivered by the 50V source
A. 271 W
B. 272 W
C. 273 W
D. 274 W
Explanation: By using source transformation the above network is reduced and current in the circuit is found out and later power delivered by 50V source= 50*current in the circuit= 50*5.48A= 274W.
If there are five 20V voltage sources in parallel, then in source transformation __________
A. All are considered
B. Only one is considered
C. All are ignored
D. Only 2 are considered
Explanation: In parallel, voltages are same. So, only is considered and rest are ignored.